we know that
The simple interest formula is equal to

where
P is the Principal amount of money to be invested
I is the amount of money in interest
r is the rate of interest
t is Number of Time Periods
in this problem we have

substitute in the formula above and solve for P

![P=14.65/[(0.025)(2)]](https://tex.z-dn.net/?f=P%3D14.65%2F%5B%280.025%29%282%29%5D)

therefore
<u>the answer is</u>

Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
I’m not sure maybe if there was an imagine I’d be able to answer this question.
Answer:
<em>6000 people</em>
Step-by-step explanation:
Given the ratio of in-state to out-of-state visitors to the amusement park was 4 to 3, the total ratio will be 4+3 = 7
Total visitors in the park = 14,000 visitors
Number of people that were out of state = 3/7 * 14000
Number of people that were out of state = 3 * 2000
Number of people that were out of state = 6000
<em>Hence there were 6000 people out of state.</em>
Answer:
3(n-8)
Step-by-step explanation: