<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
2x-1=0
2x=1
x=1/2
x+5=0
x=-5
Final answer: B
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2. C
3. B
4. A
5. D
6. A
Hope this helps *smiles*
Sorry if it’s wrong
Picture 2;Picture 4;Picture 1;Picture 5;and then Picture 6
Answer:
A
Step-by-step explanation:
