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3 years ago

What is the chemical formula for aloe vera gel (or just aloe vera)?

Chemistry

2 answers:

MaRussiya [10]3 years ago

8 0

Answer:

Aloeride is a polysaccharide that comprises only 0.015% of the crude A. vera juice material (dry weight). It has a molecular weight between 4 and 7 million Da with its glycosyl components containing glucose (37.2%), galactose (23.9%), mannose (19.5%) and arabinose (10.3%).

klio [65]3 years ago

3 0

Answer:

Explanation:

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Question: Which type of rock (sedimentary, metamorphic or igneous) will break apart the easiest with repeated freezing and thawi

iris [78.8K]

I'm not sure, but I believe it's the igneous rock because igneous rocks are formed with magma. If freezing water touched wicked hot lava the rock might harden but be very flimsy. Then again I'm not sure. Sedimentary is already broken down rock from weathering and erosion and metamorphic rock is a solid, normal rock that probably wouldn't react to freezing water.

6 0

4 years ago

A 25.0 ml volume of hcl solution with an unknown concentration is titrated with a 0.208 m naoh solution. neutralization of the h

telo118 [61]

A 25.0 ml volume of hcl solution with an unknown concentration is titrated with a 0.208 m naoh solution. neutralization of the hcl solution requires 26.6 ml of the naoh solution. calculate the concentration of the hcl solution

3 0

4 years ago

Hello! Help me please.<br><br>

quester [9]

Explanation:

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Sound does not travel in a vacuum

7 0

3 years ago

An atom has9 electrons and 9 protons at the start. If it loses 2 electrons, what would the net charge on the atom be

nevsk [136]

Answer:

i hope it will help you

Explanation:

there will be 7 electrons and 9 protons will have 2+ charge.

3 0

3 years ago

A. In the complete reaction of 22.99 g of sodium

fenix001 [56]

Answer : 58.44 g

<h3>Further explanation</h3>

The reaction

$\tt Na+Cl\Rightarrow NaCl$

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

mol of Na :

$\tt mol=\dfrac{22.99}{22.99}=1$

mol of Cl :

$\tt mol=\dfrac{35.45}{35.45}=1$

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

mass of NaCl :

$\tt =\dfrac{mol~NaCl}{mol~Na}\times MW~NaCl\\\\=\dfrac{1}{1}\times 58.44\\\\=\boxed{\bold{58.44~g}}$

3 0

4 years ago