For the answer to the question above, n the 1st month, the accrued interest is ___ (1/12) * .0525 * 135400
subtract the interest from the payment to find the change in the principal for the 2nd month
find the 2nd month's interest and subtract from the payment to find the amount applied to principal. Then that's it!
Answer:
1. you are the question :)
2. remainder would be 1,
Step-by-step explanation:
look it up, its easier
Answer:
y=2x+14
Not sure if that's what your looking for, but hope it helps!
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<Jayla>
=[(sinx/cosx)/(1+1/cosx)] + [(1+1/cosx)/(sinx/cosx)]
=[(sinx/cosx)/(cosx+1/cosx)]+[(cosx+1/cosx)/(sinx/cosx)]
= [sinx/(cosx+1)] + [(cosx+1)/sinx]
= [sin^2x+(cosx+1)^2] / [sinx (cosx+1)]
= [2+2cosx] / [sinx(cosx+1)]
=[2(cosx+1)] / [sinx (cosx+1)]
= 2/sinx
= 2 cscx
(I think this will be helpful for you. if you can see the picture, it has more detail in it.)
3 is the Anwser put number 3 in