All categories

2 years ago

Please find the angles

Mathematics

2 answers:

bulgar [2K]2 years ago

8 0

Answer:

<1 = 50

<2 = 40

<3 = 90

<4 = 90

<5 = 40

<6 = 50

<7 = 130

Step-by-step explanation:

<5 + <6 = 90

40 + <6 = 90

<6 = 50

<5 = <2 because of vertical angles

<2 = 40

<6 = <1 because of vertical angles

<1 = 50

<7 = <4 + <5

<7 = 90 + 40

<7 = 130

vladimir1956 [14]2 years ago

5 0

Answer:

Solution given:

<4=90°[vertically opposite angle]

<2=<5=40°[vertically opposite angle]

<3=90°[right angle]

again

<1+<2=90°[right angle]

<1=90°-40°=50°

<1=50°

again

<5=40°[given]

<6=<1=50°[vertically opposite angle]

<6=50°

again

<7=<4+<5=90°+40°=130°

You might be interested in

HIiiiiiiiiiiiiiiiiiiiiiiiii

professor190 [17]

Answer:

hi the answer is 7.3

Step-by-step explanation:

hope it helps you have a good day

8 0

3 years ago

Given: x - 6.3333 ≤ 1.5 .

Inessa05 [86]

Answer:

$x$ or $(-\infty, 47/6]$

Step-by-step explanation:

Note that $6.3333 = 6 1/3 = 19/3 = 38/6$ .

Also, note that $1.5 = 1 1/2 = 3/2 = 9/6$ .

So, the inequality is really equal to $x-38/6$ .

We can then add $38/6$ to both sides to get $x$ .

So, the solution is $x$ , or in interval notation, $(-\infty, 47/6]$

3 0

2 years ago

SOMEONE PLEASE HELP!<br>Set up an inequality showing that the radicand cannot be negative.

Stolb23 [73]

Answer:

3t-9 >= 0

Step-by-step explanation:

Original function f(t)= square root 3t-9

There cannot be a negative in the radicand therefore 3t-9 cannot equal a negative number.

6 0

3 years ago

Read 2 more answers

Evaluate -7a – 2b, if a = -1 and b = 2.

Roman55 [17]

Plug in a and be into the equations:
$- 7( - 1) - 2(2) = \\ 7 - 4 = \\ 3$

5 0

2 years ago

Read 2 more answers

What are the first three terms of the sequence modeled by the recursive function an=1/2an-1 when a1=1?

loris [4]

Answer:

Option A is correct that is $1,\frac{1}{2},\frac{1}{4}$

Step-by-step explanation:

We have been given a formula $a_n=\frac{1}{2}\cdot a_n-1$

$a_1=1$

We will put values of n in $a_n=\frac{1}{2}\cdot a_n-1$

when n=2 we get

$a_2=\frac{1}{2}\cdot a_2-1$

$\Rightarrow a_2=\frac{1}{2}\cdot a_1$

$\Rightarrow a_2=\frac{1}{2}\cdot 1$

$\Rightarrow a_2=\frac{1}{2}$

when n=3

$a_3=\frac{1}{2}\cdot a_2$

$\Rightarrow a_3=\frac{1}{2}\cdot \frac{1}{2}$

$\Rightarrow a_3=\frac{1}{4}$

Therefore, Option A is correct that is $1,\frac{1}{2},\frac{1}{4}$

6 0

2 years ago

Read 2 more answers