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3 years ago

12

Hello I need someone to help me answer 10 algebra 1 math test questions i will pay money after or give brainiest on each questio

n I need it today!!

1 answer:

shtirl [24]3 years ago

6 0

Hello! i’m in algebra 2 and passed algebra 1 with a 97%. any chance i might be able to help you? i don’t want money for it tho

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What is the distance between the coordinate points (7,0), (-1,3)

JulijaS [17]

Step-by-step explanation:

in moving from the point let say A(7,0) to the point B(-1,3), the x-coordinate increases by (7-(-1)= 8 while the y-coordinate decreses by (0-3)=-3. The same of this is given by finding the square of 8=64 and (-3)=9. by summing the two we have 64+9=73. so we find the square root of 73 which which is 8.55. so therefore the answer is 8.55 which is approximately 9

4 0

3 years ago

Write a decimal that is one tenth of 0.9

vladimir2022 [97]

0.1 is 1/10 of 0.9
You can divide 0.9 by 0.1

7 0

3 years ago

Let h(x)=e−x+kx, where k is any constant. For what value(s) of k does h have (a) No critical points? (b) One critical point? (c)

mrs_skeptik [129]

Answer:

a) for k≤0 , h has no critical point

b) for k>0 , h has a critical point

c) for k=0 , has a horizontal asymptote

Step-by-step explanation:

for the function

h(x)=e^(−x)+k

h has a critical point when the first derivative is =0 or is undefined. Since e^(−x) and k*x are continuos functions for all x then the second case is discarded. Then

dh/dx = -e^(−x)+k = 0

k = e^(−x)

x = ln (1/k)

since ln (1/k) should be possitive then k should be >0 . Thus h(x) has a critical point when k>0 and do not have any when k≤0

h has a horizontal asymptote when

lim h(x)=a when x→∞ (or -∞)

then

when x→∞, lim h(x)= lim e^(−x)+k*x = lim e^(−x) + k* lim x = 0 + k*∞ = ∞

on the other hand , when k=0 , lim h(x)= lim e^(−x)= 0 , then h has a horizontal asymptote for k=0

for x→(-∞) , e^(-x) rises exponentially , thus there is no k such that h has an horizontal asymptote when x→(-∞)

6 0

3 years ago

how much would you need to deposit in an account now in order to have 6000 in the account in 8 years. assume the account earns 6

Katen [24]

<h3>Answer:</h3>

$3,717.14

<h3>Step-by-step explanation:</h3>

Compound interest is the interest on the principal funding as well as the interest itself.

Compound Interest Formula

Compound interest can be solved by plugging known values into a formula.

$A = P(1 + \frac{r}{n})^{nt}$

In this formula, the variables stand for different values.

A = total amount
P = principal amount
r = rate as a decimal
n = times compounded per time period
t = time

So, for this question, we can plug in the values we are given and solve for P.

Identifying Known Values

First, let's find the exact numbers we are going to plug in.

6000 is the final amount we want, so A = 6000.
6%, the rate, is 0.06 as a decimal, so r = 0.06.
Since interest is compounded each month per year, n = 12.
The total time is 8 years, so t = 8.

Solving For P

Now we can plug all of these values in.

$6000=P(1+\frac{0.06}{12})^{12*8}$

First, simplify the values within the parentheses and in the exponent through arithmetic.

$6000 = P(1.005)^{96}$

Next, divide both sides by $1.005^{96}$

3717.14 ≈ P

*Note that the answer has been rounded to the nearest hundredth.

This means that you would need to deposit $3,717.14 into the account to have $6,000 in 8 years.

6 0

2 years ago

Money that is paid for borrowing someone else's money.

Margarita [4]

Answer:

debit

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers