Answer:
Points are given corresponding to (-8,0) and (0,-11), and you want line's equation in the form y=mx+b. Understand, you already have b=-11. If you too understand ...
Step-by-step explanation:
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
28 hope this helps if it does thank me later
Answer:
![p=10\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D10%5Csqrt%5B3%5D%7B54%7Dx%5E2)
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
![a=2\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=a%3D2%5Csqrt%5B3%5D%7B54%7Dx%5E2)
![b=3\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=b%3D3%5Csqrt%5B3%5D%7B54%7Dx%5E2)
now, we can find perimeter
perimeter=2a+2b
so, we get
![p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)](https://tex.z-dn.net/?f=p%3D2%282%5Csqrt%5B3%5D%7B54%7Dx%5E2%29%2B2%283%5Csqrt%5B3%5D%7B54%7Dx%5E2%29)
we can simplify it
![p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D4%5Csqrt%5B3%5D%7B54%7Dx%5E2%2B6%5Csqrt%5B3%5D%7B54%7Dx%5E2)
................Answer
Answer:
18
Step-by-step explanation: