Ask question

Ask question

All categories

2 years ago

10

The weights of a breed of dog are normally distributed with mean 22 lbs and standard deviation 1.6 lbs. Out of randomly selected

sample to 200 dogs. How many might you expect to weigh more than 23 lbs? Round your answer to the nearest whole dog.

1 answer:

ser-zykov [4K]2 years ago

5 0

Answer: C or

41*67/2=1373.5

Step-by-step explanation:

Hi

You might be interested in

Please help me solve this

Sever21 [200]

The answer is C) all real numbers greater than or equal to one.

Hope this helps!

4 0

2 years ago

Links will be reported

Oxana [17]

Answer:

Center: (-2, 4)

Radius: 4

Step-by-step explanation:

To find the centre and radius, we require to identify g , f and c

By comparing the coefficients of 'like terms' in the given equation with the general form.

2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)

radius = √22+(−4)2−4= √4+16−4=4

Center: (-2, 4)

Radius: 4

Hope This Helps! :)

8 0

2 years ago

Find the perimeter of ADE

irga5000 [103]

At D point in the bottom then up and to the right upper corner to Letter B

5 0

2 years ago

You spend $30.40 on 4 CDs. Each CD costs the same amount and is on sale for 80% of the original price.

gizmo_the_mogwai [7]

Answer: The original price is $9.5
In this question, you are given the total spending( $30.40), amount of spend (4CDs) and the discounted price(80%). Then to find the original price of the CD, the calculation would be:

Total spending = amount of cd x CD discounted price
$30.40 = 4 x 0.8 Original price
3.2 Original price= $30.40
Original price= $9.5

4 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

<u><em>Step(ii)</em></u>:-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

<u><em>verification </em></u>:-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago