If you distribute -4 through (5k-7), it equals -20k + 28. Then put on the other -2k on that side of the equals sign and you should have -22k + 28 = -2(9k+5) Then you need to distribute -2 through (9k+5) which equals -18k - 10. You then should have -22k+28=-18k-10. Add 22k to both sides to cancel it out, then you should have 28=4k-10. Add 10 to both sides to get the 4k by itself, which will be 38=4k, then divide both sides by 4 to get k by itself. 38/4 = 19/2. k = 19/2
Answer:
B. The two lines are neither parallel nor perpendicular.
Step-by-step explanation:
First, put both lines into the same format. In this example, we're going to use y=mx+b format.
x - 4y = -9
-4y = -x + -9
y = (-x + -9) / -4
y = (x+9)/-4
y = (-1/4)x + (-9/4)
y = 3x - 7
If two lines are parallel, they have the same slope. (ie 4 and 4)
If two lines are perpendicular, one line's slope is the negative reciprocal of the other. (ie 4 and -1/4)
Neither is true here.
Answer:
Total number of combination = 32
Step-by-step explanation:
Given:
Number of cars = 3
Number of models = 2.
Number of color = 4
Find:
Total number of combination
Computation:
Total number of combination = [2³ x (2x3) x 4] / !3
Total number of combination = 32
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z = 
~ N(0,1)
where, 
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( 
12)
P( 12) = P( 
) = P(Z 1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
