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stira [4]
3 years ago
8

What is the product of 845 x 58??? (I’m bad at multiplication ;-;)

Mathematics
2 answers:
pentagon [3]3 years ago
8 0
Hi there!

845 * 58 = 19010

Hope this helps!
Nastasia [14]3 years ago
3 0

Your answer is 49,010. If you need any more help or assistance, ask me. I don't mind being your tutor.

- Tyler

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trasher [3.6K]

3 goes into 42 14 times


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3 years ago
I need to find area of this shape
aleksklad [387]

Answer:

15 in

Step-by-step explanation:

LxH

3 0
3 years ago
What is the solution to the equation
Dafna11 [192]
\sqrt{4t+5}=3-\sqrt{t+5}\\\\D:4t+5\geq0\ \wedge\ t+5\geq0\ \wedge\ \sqrt{t+5}\leq3\\\\t\geq-\dfrac{5}{4}\ \wedge\ t\geq-5\ \wedge\ t\leq6

therefore
D:x\in\left< -\dfrac{5}{4};\ 6\right>

\sqrt{4t+5}=3-\sqrt{t+5}\ \ \ |^2\\\\(\sqrt{4t+5})^2=(3-\sqrt{t+5})^2\ \ \ |use:(a-b)^2=a^2-2ab+b^2\\\\4t+5=3^2-2\cdot3\cdot\sqrt{t+5}+(\sqrt{t+5})^2\\\\4t+5=9-6\sqrt{t+5}+t+5\ \ \ \ |-t\\\\3t+5=14-6\sqrt{t+5}\ \ \ \ |-14\\\\3t-9=-6\sqrt{t+5}\ \ \ \ |change\ signs
9-3t=6\sqrt{t+5}\ \ \ \ |:3\\\\3-t=2\sqrt{t+5}\ \ \ \ |^2\\\\(3-t)^2=(2\sqrt{t+5})^2\\\\3^2-2\cdot3\cdot t+t^2=4(t+5)\\\\9-6t+t^2=4t+20\ \ \ |-4t-20\\\\t^2-10t-11=0\\\\t^2+t-11t-11=0\\\\t(t+1)-11(t+1)=0\\\\(t+1)(t-11)=0\iff t+1=0\ \vee\ t-11=0\\\\t=-1\in D\ \vee\ t=11\notin D
Answer: t = -1.


7 0
3 years ago
Read 2 more answers
Please help!!!!!I’ll mark you as brainliest!!!!!!
Sav [38]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
13) The side length of the following cube is 8 cm. what is the length of the diagonal through its center?​
Scorpion4ik [409]

Answer: \sqrt{3} x 8 = 13.8564064606

Step-by-step explanation: The main diagonal of any cube can be found by multiplying the length of one side by the square root of 3 (\sqrt{3}). Therefore, square root 3 (\sqrt{3}) is multiplied by the length (8 in our case) of either 6 faces of the cube.

Hope it helped!

5 0
3 years ago
Read 2 more answers
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