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3 years ago

ASAP all answers 5-8 pls

Mathematics

1 answer:

SashulF [63]3 years ago

4 0

7. SRQ
8. M
You have 5 and 6 correct

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Please Help Me On These Questions!!!!!! I need Help!!!!!

melisa1 [442]

1. This is one confusing question... But here is what I did
x = 2y + 1
y = $3y^{2}$ + 2x

So plug in Y to solve for X
x = 2 ( $3y^{2}$ + 2x) + 1
x = $-2y^{2}$ - $\frac{1}{3}$
Not sure if that's completely correct, but I'm positive I didn't make any mistakes...

5. You have to find the multiples of 60 so...

1 60
2 30
3 20
4 15
5 12 <---

7 = 12 - 5

4 0

3 years ago

Solve for x: 3 − (2x − 5) < −4(x + 2)

Firdavs [7]

Answer:

A. x < -8 (first option)

Step-by-step explanation:

$3 - (2x - 5) < - 4(x + 2)$

$3 - 2x + 5 < - 4x - 8$

$8 - 2x < - 4x - 8$

$- 2x + 4x < - 8 - 8$

$2x < - 16$

$\boxed{\green{x < - 8}}$

6 0

3 years ago

5.65 as a mixed number.

katrin2010 [14]

Answer= 5 13/20

.65=65/100
simplify the fraction by dividing both numbers by 5
65/100=13/20

So 5.65=5 13/20

6 0

4 years ago

Read 2 more answers

Find -x + 10 subtracted from 0. 0 -x + 10 x - 10

Finger [1]

0 - (-x + 10)

a negative subtracted from something is a positive.

0 + x - 10

Your answer is x - 10

Hope I helped!

Let me know if you need anything else!

~ Zoe

8 0

3 years ago

Read 2 more answers

g A cannonball is shot with an initial speed of 62 meters per second at a launch angle of 25 degrees toward a castle wall that i

IceJOKER [234]

Answer:

h = 16.23 m

The cannonball will hit the wall at 16.23m from the ground.

Step-by-step explanation:

Given;

Initial speed v = 62m/s

Angle ∅ = 25°

Horizontal distance d = 260 m

Height of wall y = 20

Resolving the initial speed to vertical and horizontal components;

Horizontal vx = vcos∅ = 62cos25°

Vertical vy = vsin∅ = 62cos25°

The time taken for the cannon ball to reach the wall is;

Time t = horizontal distance/horizontal speed

t = d/vx (since horizontal speed is constant)

t = 260/(62cos25°)

t = 4.627 seconds.

Applying the equation of motion;

The height of the cannonball at time t is;

h = (vy)t - 0.5gt^2

Acceleration due to gravity g = 9.81 m/s

Substituting the given values;

h = 62sin25×4.627 - 0.5×9.81×4.627^2

h = 16.2264134736

h = 16.23 m

The cannonball will hit the wall at 16.23m from the ground.

8 0

4 years ago