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3 years ago

14 - (2x + 5) = -2x +9 How do you solve this problem?

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

5 0

Answer:

x ∈ R (all reals)

Step-by-step explanation:

14 - (2x + 5) = -2x + 9

Take out parentheses

14 - 2x - 5 = -2x + 9

Simplify

9 = 9

<em>Since 9 does equal 9, it means that this equation can be true for all real values of x.</em>

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What is 25.4067 rounded to the nearest hundredth ?

andreev551 [17]

Answer:your answer is 25.41

Step-by-step explanation:

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3 years ago

Given that DE is a midsegment for ABC and the length of DE is 8 units. What is the length of BC?

tresset_1 [31]

Answer:

BC = 16 units

Step-by-step explanation:

Since DE is the midsegment of the triangle, based on the midsegment theorem, thus:

DE = ½(BC)

DE = 8 units

Plug in the value

8 = ½(BC)

Multiply both sides by 2

2*8 = BC

BC = 16 units

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3 years ago

Can someone plz help me with this problem plz

wolverine [178]

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3 years ago

How many solutions are there to the system of equations? StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negat

kkurt [141]

Answer:

Only one solution $x=\frac{5}{4},y=0$

Step-by-step explanation:

$4x-5y=5..............(1)\\0.08x+0.10y=0.10...........(2)$

Multiply equation $(2)$ by $50$

$4x-5y=5........(3)$

Now from equation $(1)$ $+$ equation $(3)$

$8x=10\\x=\frac{10}{8}\\x=\frac{5}{4}$

Put the value in equation $(1)$

$5-5y=5\\5y=0\\y=0$

hence only one solution exists $\left(\frac{5}{4},0\right)$ .

3 0

3 years ago

Read 2 more answers

Do line segments with the given lengths form a right triangle? State whether the line segments with the given lengths form a rig

Dvinal [7]

Given:

19, 180, 181

To be able to determine if the given lengths form a right triangle, the following condition must be met:

$\text{ a}^2\text{ + }b^2=c^2$

Let's check.

a.) At a = 19, b = 180, c = 181

$\begin{gathered} \text{ a}^2\text{ + }b^2=c^2 \\ (19)^2+(180)^2=(181)^2 \\ 361\text{ + 32,400 = 32,761} \\ 32,761\text{ = 32,761} \end{gathered}$

Therefore, the given lengths could form a right triangle at a = 19, b = 180 and c = 181.

The answer is yes.

It just happened to be that we got the right answer on the first try, you must also examine at a = 180, b = 181, c = 19 and a = 181, b = 19, c = 180 if the first try didn't meet the right condition.

If you failed to get, then the given lengths could not form a right triangle. The answer would be no.

4 0

1 year ago