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Andreas93 [3]
3 years ago
11

Help me answer question 1 . ​

Mathematics
1 answer:
kolezko [41]3 years ago
7 0
C. is the right answer I think so at least
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i dont know for shore but i think it is part 2

Step-by-step explanation:

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weeeeeb [17]

Answer:

0.0367 = 3.67% probability that exactly 6 patients will die

Step-by-step explanation:

The patients are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

20 patients means that N = 20

Sample of 8 means that n = 8

9 have the heart problem, so k = 9

What is the probability that exactly 6 patients will die?

This is P(X = 6).

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 6) = h(6,20,8,9) = \frac{C_{9,6}*C_{11,2}}{C_{20,8}} = 0.0367

0.0367 = 3.67% probability that exactly 6 patients will die

3 0
3 years ago
City health officials will conduct a two-sample t-test for a difference in means to investigate whether
Anvisha [2.4K]

Answer:

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

The null hypothesis is rejected

There is a difference between the means      

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the first sample size 'n₁' = 22

Given that the mean of the first sample x₁⁻ = 120

Given that the standard deviation of the sample (s₁) = 20

Given that the mean of the second sample x₂⁻ = 100

Given that the standard deviation of the second sample (S₂) = 30

<u><em>Step(ii):-</em></u>

T-test statistic

               t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }

     where

             S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2} S_{2} ^{2}   }{n_{1} +n_{2}-2 }

            S^{2} = \frac{22( 20)^{2}+ 15(30) ^{2}   }{22 +15-2 }

           S² =  637.1428

           S = √637.1428 = 25.24168  

The standard deviation of the sample 'S' = 25.24168   

<u><em>Step(iii):-</em></u>

<u><em>Null Hypothesis:H₀:</em></u>

There is no difference between the means

<u><em>Alternative Hypothesis:H₁:</em></u>

There is a difference between the means

         T-test statistic

               t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }

              t = \frac{ 120 -100 }{\sqrt{637.14 (\frac{1}{22 }+\frac{1}{15 } ) } }

             t =   2.366

Degrees of freedom

           γ = n₁+n₂ -2 = 22+15-2 = 35

     t₀.₀₅ = 2.0301

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

The null hypothesis is rejected

There is a difference between the means          

3 0
3 years ago
Read 2 more answers
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