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Andreas93 [3]
3 years ago
11

Help me answer question 1 . ​

Mathematics
1 answer:
kolezko [41]3 years ago
7 0
C. is the right answer I think so at least
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Which of the following is a correct interpretation of the expression -7- (-11)?
Brilliant_brown [7]

Answer:

B. Start at -7 on the number line and move 11 to the right.

Step-by-step explanation:

<u>Given:</u>

  • - 7 - (-11) expression

We can add or remove only positive numbers on the number line to get it  correct, so we need to open the parenthesis. When evaluated we get:

-7- (-11) = - 7 + 11 = 4

<u>Correct interpretation of of this expression is:</u>

  • Start at -7 and add 11, thus move 11 points to the right, to get 4 as final point.

<u>Correct choice is:</u>

  • B. Start at -7 on the number line and move 11 to the right.

6 0
3 years ago
Which two substances bind using a lock-and-key mechanism?
kherson [118]

Answer:

enzyme and substrate. reactant and substrate. substrate and product.

Step-by-step explanation:

4 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
A bottle of tnt tonic contains 10 1/2 ounces and sells for 98¢ what is the cost per ounce
Rashid [163]

0.09 is the answer, hope this helps

4 0
3 years ago
Given f(x) = x^2 + x − 2 and g(x) = 2x − 4, identify (f + g)(x).
shutvik [7]

Answer:

(f + g)(x) = x^2 + 3x - 6

Step-by-step explanation:

Given f(x) = x^2 + x − 2 and g(x) = 2x − 4

Plug in:

(f + g)(x) = x^2 + x − 2 + 2x − 4

(f + g)(x) = x^2 + 3x - 6

3 0
3 years ago
Read 2 more answers
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