Answer:
8 (see work)
14. 2x^2 -4x^2 +3
Step-by-step explanation:
There's attached work for explanation
We can solve with a system of equations, and use c for the amount of cans of soup and f for the amount of frozen dinners.
The first equation will represent the amount of sodium. We know the (sodium in one can times the number of cans) plus (sodium in one frozen dinner times the number of dinners) is the expression for the total sodium. We also know the total sodium is 4450, so:
250c + 550f = 4450
The second equation is to find how many of each item are purchased:
c + f = 13
Solve for c in the second equation:
c = 13 - f
Plug this in for c in the first equation:
250(13-f) + 550f = 4450
3250 - 250f + 550f = 4450
300f = 1200
f = 4
Now plug the value for f into the second equation:
c + 4 = 13
c = 9
The answer is 9 cans of soups and 4 frozen dinners.
Answer:

Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when x is 0) - Parallel lines always have the same slope
<u>1) Determine the slope of line S using line R (m)</u>

We can identify clearly that the slope of the line is
, as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be
. Plug this into
:

<u>2) Determine the y-intercept of line S (b)</u>

Plug in the given point (-4,3) and solve for b

Subtract 1 from both sides to isolate b

Therefore, the y-intercept is 2. Plug this back into
:

I hope this helps!
Answer:
+49
Step-by-step explanation:
-7 x -7 = +49 because the negatives cancel out, resulting in a positive
Answer:

And if we want to find
we can use this formula from the definition of independent events :

And the best option would be:

Step-by-step explanation:
For this case we have the following events A and B and we also have the probabilities for each one given:

And if we want to find
we can use this formula from the definition of independent events :

And the best option would be:
