Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
Answer:
Inequalities are,
y ≥ 4x + 2
y ≥ 2
Step-by-step explanation:
Solid yellow line of the graph attached passes through two points (0, -2) and (1, 2).
Let the equation of this line is,
y = mx + b
Slope of the line = 
m = 
m = 4
Y-intercept 'b' = -2
Equation of the line will be,
y = 4x - 2
Since shaded area is on the left side of this solid line so the inequality representing this region will be,
y ≥ 4x - 2
Another line is a solid blue line parallel to the x-axis.
Shaded region (blue) above the line will be represented by,
y ≥ 2
Therefore, the common shaded area of these inequalities will be the solution of the given inequalities.
I think it’s D but not completely sure!
A right triangle can only be formed when you use the 3/4/5 rule.
The 3/4/5 rule is a^2 + b^2 = c^2.
We will use 10 for a, 15 for b, and 20 for c.
a^2 + b^2 = c^2
Plug in 10 for a, 15 for b, and 20 for c.
10^2 + 15^2 = 20^2
10^2 = 100
15^2 = 225
20^2 = 400
100 + 225 = 400
This is not applicable, as 100 + 225 = 325.
Your answer is:
No, 10,15,20 does not form a right triangle.
I hope this helps!