1) 2, greater than (>)
4/5 = 8/10
8/10 (4/5) > 2/10
2) 1, less than (<)
3/8 = 30/80 | 6/10 = 48/80
30/80 (3/8) < 48/80 (6/10)
Hope this helps! :)
Answer:
Step-by-step explanation:
hello :
The circumference of the circle is 20π inches
The length of the arc is (72/360)×20π = 12.6 inches
(The complete circumference would cover 360°. Angle ALB is 72°)
Answer:
i think its
-8
negitive
up
minimum
Step-by-step explanation:
The coordinate grid is 96 x 96. This means that there are 96*96=96^2 squares . In order to find the number of bits we should solve the problem: 2^X>96^2
2^X>=9216
We should solve the problem by testing several options:
2^10=1024 <9216 so we need more than 10 bits to encode a coordinate in that space
2^12=4096 <9216 so we need more than 12 bits to encode a coordinate in that space
<span>2^14=16384 > 9216 so we need minimum 14 bits to encode a coordinate in that space</span>
Answer: angle ITU = 145 degrees
===============================================
Explanation:
Angle STU is the largest angle composed of the smaller angles STI and ITU.
In other words, the two smaller angles add up to the larger one.
(angle STI) + (angle ITU) = angle STU
( 20 ) + ( 12x+1 ) = 13x + 9
20+12x+1 = 13x+9
12x+21 = 13x+9
21-9 = 13x-12x
12 = x
x = 12
Using this x value, we find that,
angle ITU = 12x+1 = 12(12)+1 = 145 degrees
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As a side note,
angle STU = 13x+9 = 13(12)+9 = 165 degrees
This is confirmed with
(angle STI) + (angle ITU) = (20) + (145) = 165 = angle STU