Answer:
<em>x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
Step-by-step explanation:
See steps below;
I would prefer answering this question by completing the square, rather than applying a quadratic formula;
3x^2 - 6x - 12 = 0, ⇒ Add 12 to either side,
3x^2 - 6x = 12, ⇒ Divide either side by 3,
x^2 - 2x = 4, ⇒ Write the equation in the form x^2 + 2ax + a^2 = (x + a)^2,
x^2 - 2ax + a^2 = 4 + a^2, ⇒ Solve for a
2ax = -2x,
a = - 1, ⇒ Substitute value of a,
x^2 - 2x + 1 = 4 + 1,
( x - 1 )^2 = 5, ⇒ Solve for x,
x = √5 + 1, and x = - √5 + 1,
In other words; <em>Solution : x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
Answer:

Step-by-step explanation:
step 1
Find the measure of angle A
we know that
The sum of the interior angles in any triangle must be equal to 180 degrees
so

substitute the given values

step 2
Find the length side c
Applying the law of sines

substitute the given values

solve for c


Answer:
$3.32
Step-by-step explanation:
You take 30% of 4.75. You multiply 0.30 times 4.75. Then you subract that from 4.75. Boom.
Answer:
27
Step-by-step explanation:
200 ÷ 7 = 27
<em>good luck, i hope this helps :)</em>
Answer:

Step-by-step explanation:
The initial population of bacteria is 800 and we know that this number is quadrupling every hour.
<u>We're going to find a function in terms of t (time) that gives us the population of bacteria at that time.</u>
Since the population is quadrupling every hour the function in terms of t (where t is expressed in hours) is:

Now we need to find the time when there will be 5,120,000 bacterias. This means the time t when f(t) = 5,120,000
So we have 5,120,000 = 

Therefore, the time when there will be 5,120,000 bacterias will be:
