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3 years ago

Please show work! will give brainlist!

Mathematics

2 answers:

laila [671]3 years ago

7 0

The answer is a, 21 inches

Akimi4 [234]3 years ago

5 0

Answer:

a) 21 inches :))

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What is 15-4-12? I NEED HELP ASAP! Ps we’re learning about subtracting integers on this problem.

Tatiana [17]

It's -1.

15 - 4 = 11

11 - 12 = -1

6 0

2 years ago

Lelani has 64 baseball cards. This is 4 times as many baseball cards as Paul has. How many baseball cards does Paul have?

NemiM [27]

Answer:

Step-by-step explanation:

64 divided by 4 is 16. Paul has 16 baseball cards.

7 0

2 years ago

Read 2 more answers

Sarah's hair appointment is 30 miles away. How fast must she travel to get there in 60 minutes?

Fudgin [204]

Answer:

30 miles an hour

Step-by-step explanation:

6 0

3 years ago

30 points Help ASAP How do division properties help you evaluate expressions? Drag a word or number to the box to correctly comp

yKpoI14uk [10]

Answer:

Numerator , 0

Anything divided by 0 is always 0

Brainliest Pls

3 0

3 years ago

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$

we get:

$V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}$

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

4 0

2 years ago