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Alchen [17]
2 years ago
8

A middle school took all of its 6th grade students on a field trip to see a play at a theater that has 2780 seats. The students

left 15% of the seats in the theater vacant. How many 6th graders went on the trip?
Mathematics
1 answer:
Over [174]2 years ago
5 0

Answer:

1242 6th graders went on the trip.

Step-by-step explanation:

From the information given, you know that the theater has 2760 seats and that the students filled 45% of the seats, so to find the quantity of 6th graders that went on the trip, you have to calculate 45% of 2760:

2760*45%=1242

According to this, the answer is that 1242 6th graders went on the trip.

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About geometry transformation ​
Free_Kalibri [48]

Answer:

A geometric object is represented by its vertices (as position vectors) A geometric transformation is an operation that modifies its shape, size, position, orientation etc with respect to its current configuration operating on the vertices (position vectors).

8 0
2 years ago
There are an equal number of pennies, nickels, dimes, and quarters in a bag. What is the probability that the combined value of
Anettt [7]

Answer:

the probability is 0.09375

Step-by-step explanation:

From the question we know that there are equal number of pennies, nickels, dimes and quarters, So the probability of get of select one penny, or one nickel, or one dime or one quarter is the same. This is equivalent to have one of every coin and select four with replacement.

Additionally, the only way that the combined value of the four coins selected will be $0.41 is that the person select one penny, one nickel, one dime and one quarter.

The total ways of select 4 coins from 4 types of coins is calculate by the rule of multiplication as:

4*4*4*4=256

And for obtain the value of $0.41 the number of ways are:

4*3*2*1=24

Then the probability that the combined value of the four coins randomly selected with replacement will be $0.41 can be calculated as:

P=24/256=0.09375

8 0
3 years ago
9 yards times 3 over 1 times 2 over 1 =54 over 1
I am Lyosha [343]

Answer:

yeah

Step-by-step explanation:

thanks, 5 star, brainliest pls

4 0
3 years ago
Carrie borrowed $800 dollars from her aunt at 8% interest per year. If she paid her a total of $448 in simple interest, how many
Jet001 [13]

Answer:

13 years

Step-by-step explanation:

First we will have to see how much she owns her aunt:

800-448= 362

8% of 348 = 27.84

362 ÷ 27.84 = 13 years

I might be wrong but hopefully this helps :)

8 0
2 years ago
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
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