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3 years ago

Evaluate the function rule for the given value.

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

5 0

the answer is 25

raise 5 to the power of 2 and you get 25

Lena [83]3 years ago

3 0

Answer:

Option C - 10

Step-by-step explanation:

Given : Function $f(x)=5x$

To find : Evaluate the function for the value x=2

Solution :

We have given the function $f(x)=5x$

We have to find the value of f(x) at x=2

Substitute x=2 in the given function f(x)

$f(x)=5x$

$f(2)=5(2)$

$f(2)=10$

Therefore, Option C is correct.

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Consider the two groups listed below. Which statement describes the sets?

IceJOKER [234]

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3 years ago

3. Simplify: 13.6 - 4.1 - 3.8 + 6.7

Art [367]

Answer:

12.4 is the answer

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5 0

3 years ago

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What is the area of a triangle that has a height of 6 feet and a base length of 7 feet? (5 points)

Oksanka [162]

Formula= Base times height divided by 2

6 x 7= 42
42/ 2
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3 0

3 years ago

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For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago

lesantik [10]

Sorry i dont know this one

5 0

3 years ago

Read 2 more answers