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2 years ago

Whats the answer for number 3?

Mathematics

1 answer:

Kaylis [27]2 years ago

6 0

Answer:

B. There are no discounts or charges per month.

Step-by-step explanation:

Hope this helps. Pls give brainliest.

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The perimeter of the regular polygon shown is 14 ft.

Oliga [24]

The answer is C. 2.8!!!!!!!!

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3 years ago

Simplify the expression -2(y-1)+3(y+2)

romanna [79]

Answer: y+8

Step-by-step explanation:

-2(y-1)+3(y+2)

-2y+2+3y+6

y+8

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3 years ago

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If a car salesman made $2450 from a 12% commission on a car sale, what is cost of the car he sold?

n200080 [17]

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3 years ago

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8000$ is invested in an account the yields 6% interest per year. After how many years will the account worth 13709.60$ if the in

ozzi

Answer:

After 9 years the account will be worth 13709.60$

Step-by-step explanation:

We are given the following in the question:

We are given the following in the question:

P = $8000

r = 6% = 0.046

n = 12

The compound interest is given by:

$A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

where A is the amount, p is the principal, r is the interest rate, t is the time in years.

Putting the values, we get,

$13709.60 = 8000\bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\dfrac{13709.60}{8000} = \bigg(1+\dfrac{0.06}{12}\bigg)^{12t}\\\\\Rightarrow 1.7137 = (1.005)^{12t}\\\Rightarrow t \approx 9$

Thus, after 9 years the account will be worth 13709.60$

5 0

3 years ago

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The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

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3 years ago