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3 years ago

The first three terms of a sequence are given. Round to the nearest thousandth (if

Mathematics

1 answer:

Mumz [18]3 years ago

6 0

Answer:

$\frac{3}{16}$

Step-by-step explanation:

The common ratio is $\frac{1}{2}$

24, 12, 6, 3, $\frac{3}{2}$ , $\frac{3}{4}$ , $\frac{3}{8}$ , $\frac{3}{16}$

so divide each term by 2

<em>plz mark m brainliest. :)</em>

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olga2289 [7]

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8 0

2 years ago

Which function has a range of {y|y ≤ 5}?

Readme [11.4K]

Answer:

B(x)=(x_4)^2+5 that is the answer

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3 years ago

How do I solve y+5x=2;-1,0,1 ?

vfiekz [6]

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2 years ago

Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.

borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this question:

$n = 14, p = 0.8$

P(x>10)

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501$

$P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501$

$P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539$

$P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440$

$P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981$

So P(x > 10) = 0.6981.

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3 years ago

Patrick has a $1000 bond with a 6% coupon. Howmuch interest will Patrick receive for this bond every 6 months?

alexandr1967 [171]

Its either 300 or 12

3 0

3 years ago