If you would like to solve (- 0.5) / (- 0.5) and - 50 / (- 0.5), you can do this using the following few steps:
(- 0.5) / (- 0.5) = 0.5 / 0.5 = 1
- 50 / (- 0.5<span>) = 50 / 0.5 = 50 / (5/10) = 50 / (1/2) = 50 * 2/1 = 100
</span>
The correct results would be: (- 0.5) / (- 0.5) = 1 and - 50 / (- 0.5<span>) = 100.</span>
Answer: (0, -3/7)
Step-by-step explanation:
The Y-intercept would be the value of y when x is at 0, which is when the Y axis is intercepted. -3/7 is the starting position of the function when the the X = 0.
Answer: " 15 % " .
_______________________________
→ " 12 is <u> 15% </u> of 80 " .
_______________________________
Step-by-step explanation:
_______________________________
12 = (n/100) * 80 ;
12 = (80n) /100 ; Solve for "n:
Note: 80/100 = (80/10) / (100/10) = (8/10) = 0.8 ;
12 = (0.8)n ;
↔ (0.8n) = 12
Multiply each side of the equation by "10" ; to get rid of the "decimal" ;
10 * (0.8n) = 10 * 12 ;
to get:
_______________________________
8n = 120 ;
Divide each side of the equation by "8" ;
to isolate "n" on ONE SIDE of the equation; & to solve for "n" ;
8n/8 = 120/ 8 ;
_______________________________
to get:
_______________________________
n = 15 .
_______________________________
Answer: " 15 % " .
_______________________________
→ " 12 is <u> 15% </u> of 80 " .
_______________________________
Hope this helps!
Best wishes!
_______________________________
We know that the area of a circle in terms of π will be πr². However the area with respect to the diameter will be a different story. The first step here is to find a function relating the area and diameter of any circle --- ( 1 )
For any circle the diameter is 2 times the radius,
d = 2r
Therefore r = d / 2, which gives us the following formula through substitution.
A = π(d / 2)² = πd² / 4
<u>Hence the area of a circle as the function of it's diameter is A = πd² / 4. You can also say f(d) = πd² / 4.</u>
Now we can substitute " d " as 4, solving for the area ( A ) or f(4) --- ( 2 )
f(4) = π(4)² / 4 = 16π / 4 = 4π - <u>This makes the area of circle present with a diameter of 4 inches, 4π.</u>
A group of people help each other cope with a particular problem.