<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)
The measures of center and variability for the
temperatures that were lower this week than last week include mean, range, mean absolute deviation.
<h3>What is a mean?</h3>
It should be noted that a mean simply means the average set if numbers given.
Also, the range is the difference between the highest number and the lowest number in the data.
Learn more about mean on:
brainly.com/question/1136789
#SPJ1
Answer:
The area of the right triangle is 262.5
Step-by-step explanation:
24 because 12 + 12 = 24 and and CD = DB
CB = CD + CB = 24 the triange ADC and ADB are equal
Exponent rule : (a^b)^c = a^(b*c)
31. (x^2)^3 = x^(2 * 3) = x^6
32. (a^7)^5 = a^(7 * 5) = a^35
33. (y^13)^4 = y^(13 * 4) = y^52
34. (w^-21)^-15 = w^(-21*-15) = w^315
35. (5^2)^3 = 5^(2 * 3) = 5^6
36. (23^7)^8 = 23^(7 * 8) = 23^56
37. (-y^5)^4 = -y^(5 * 4) = y^20
38. (4y^3)^2 = 4^2 y^(3 * 2) = 16y^6
39. (8c^5)^2 = 8^2 c^(5 * 2) = 64c^10
40. (-3h^9)^2 = -3^2 h^(9 * 2) = 9h^18
41. (y^4d^6)^3 = y^(4 * 3)d^(6 * 3) = y^12d^18
42. (-15h^9k^7)^3 = -15^3h^(9*3)k^(7*3) = -3375h^27k^21
43. (k^9)^5(k^3)^2 = k(9 * 5)k^(3 * 2) = (k^45)(k^6) = k^51
44. (3y^6)^2 (x^5y^2z) = 3^2y^(6*2)(x^5y^2z) = 9y^12(x^5y^2z) =
9x^5y^14z
45. (4h^3)^2 (-2g^3h)^3 = 4^2h^(3*2) (-2^3g^(3*3)h^3) = 16h^6(-8g^9h^3)
= -128g^9h^9
46. (14a^4b^6)^2 (a^6c^3)^2 = 14^2a^(4*2)b^(6*2) (a^(6*2)c^(3*2) =
196a^8b^12(a^12c^6) = 196a^20b^12c^6