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2 years ago

10

Find the value of x. 6 X 9 x=

1 answer:

VLD [36.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

Because the distance from the center of the circle to each of those chords is 6, then there's a theorem that says that the chords are also the same length. Because on portion of one of those chords is marked with a single slash mark and measures 9, then the other part of that same segment, also marked with a single slash mark is 9. That makes the whole segment measure 18. Assuming that x is indicative of the whole segment and not just a portion of it, then x = 18

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Find the value of Y for the function below when the value of X is 14. Y= 3 Xsquared + 17

elena-14-01-66 [18.8K]

X=14
y=3x^2+17
y=3(14)^2+17
y=3•196+17
y=588+17
y=605

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Step-by-step explanation:

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2 years ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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2 years ago

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