Answer:
(i) $34,200
(ii) $55,860
(iii) $23,960
Explanation:
Total sales = $ 240,000 + $392,000 + $168,000
= $800,000
Department 1:
sales = $240,000
Percent of total = sales ÷ Total sales
= $240,000 ÷ $800,000
= 0.3
Allocated amount = % of total × advertising to allocate
= 0.3 × $114,000
= $34,200
Department 2:
sales = $392,000
Percent of total = sales ÷ Total sales
= $392,000 ÷ $800,000
= 0.49
Allocated amount = % of total × advertising to allocate
= 0.49 × $114,000
= $55,860
Department 3:
sales = $168,000
Percent of total = sales ÷ Total sales
= $168,000 ÷ $800,000
= 0.21
Allocated amount = % of total × advertising to allocate
= 0.21 × $114,000
= $23,940
Saving period = 70 - 50 = 20 years
Number savings, n = 20*12 = 240 months
Monthly savings, P = $300
Annual interest rate = 4% = 0.04
Monthly interest rate, r = 0.04/12
If FV is the amount saved at the time of retirement,
FV = P{(1+r)^n-1)/r} = 300{(1+0.04/12)^240-1)/0.04/12} = $110,032.39
Answer:
This is because the Standard Addition is more likely to give a more definite measurement of the target concentration of analyte in the sample as compared to employing a calibration curve.
In a situation where sample matrix also gives to the analytical signal and establishing a situation called the matrix effect, Standard Additions is the best option to employ rather than calibration curve.
Answer:
8% hope it helps mark it as brainliest
<span>$5648.85
The formula for compound interest is
A = P(1+r/n)^(nt)
where
A = Amount of money at end of period
P = Initial principle
r = Rate of interest
n = number of compound periods per yet
t = number of years.
So let's plug the numbers into the formula
A = P(1+r/n)^(nt)
A = 1680(1+0.0825/2)^(2 * 15)
A = 1680(1 + 0.04125)^30
A = 1680(1.04125)^30
A = 1680(3.362408)
A = $5648.85</span>
