If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Answer:
the answer is C
Step-by-step explanation:
if you do 5+10+7+2 you get 24 divide by 4 you get 6 mean is 6 for set 1
Set 2 if you do 5+10+7+42 you get 64 divide by 4 and you get 16 16-10.5 you get so 5.5 set is less than set 2 there ya go dude
Pretty much, write two problems that equal to 0
Answer:
To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.
V=43(π)(r3)
In this equation, r is equal to the radius. We can plug the given radius from the question into the equation for r.
V=43(π)(123)
Now we simply solve for V.
V=43(π)(1728)
V=(π)(2304)=2304π
Answer is 2304
