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SVEN [57.7K]
4 years ago
7

I need help pleaseeee

Mathematics
2 answers:
bekas [8.4K]4 years ago
6 0

Answer:

20cm

Step-by-step explanation:

pythagorean theorem

15^2 + b^2 = 25^2

225 + b^2 = 625

b^2 = 400

b = 20

goblinko [34]4 years ago
4 0

Answer:

20 cm

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 +b^2 = c^2

where a and b are the legs and c is the hypotenuse

15^2 +b^2 = 25^2

225+b^2 = 625

Subtract 225 from each side

225+b^2 -225 = 625-225

b^2 = 400

Take the square root of each side

sqrt(b^2) = sqrt(400)

b = 20

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X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
2 years ago
Pls give me an answer to this!!!!!!!
gayaneshka [121]

Answer:

  1. CONSTRUCT FROM A TO B AND ALSO A TO C AND B TO C
5 0
3 years ago
Circle 1: center (8, 5) and radius 6
PolarNik [594]
We have that
<span>Circle 1: center (8, 5) and radius 6
</span><span>Circle 2: center (−2, 1) and radius 2

we know that
the equation of a circle is
(x-h)</span>²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4

using a graph tool 
see the attached figure

Part A)<span>What transformations can be applied to Circle 1 to prove that the circles are similar?

we know that
r1/r2---------> 6/2------> 3
</span><span>
to prove that the circle 1 and circle 2 are similar, the radius of circle 1 </span>must be divided by 3 and  translate the center of the circle 1  (10) units to the left and (4) units down  
<span>
 the answer part A) is
</span>the radius of circle 1 must be divided by 3 and  translate the center of the circle 1  (10) units to the left and (4) units down  


Part B) <span>What scale factor does the dilation from Circle 1 to Circle 2 have?

the answer Part B) is 
the scale factor is (3/1)</span>

6 0
3 years ago
I need help with this please help me ​
Tatiana [17]

Answer:last one

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If f(x) = 3LX-2], what is f(5.9)? 9 10 11 12​
Black_prince [1.1K]

Answer: 12

Step-by-step explanation:

We know that , the ceiling function y = [x] is also known as the least integer function that gives the smallest integer greater than or equal to x.

For example : For x= 1.5

y = [1.5] =2

For x= 3.64

y = ⌊3.64⌋=4

The given function :

Then, for x= 5.9 , we have

[since [3.9]=4 (least integer function)]

Therefore, the value of f(5.9) is 12

6 0
3 years ago
Read 2 more answers
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