So let's take a peek at both's ages, keep in mind, every year, is 1year added to Irene and 1year added to Fred
so... if we look at their ages

notice, Fred is always 40years older than Irene
thus, whatever age Irene is, let's say "i", then Fred is " i + 40 "
now, when is Fred 5 times Irene's age or 5*i or 5i? well,
f = fred's age i = irene's age
f = i + 40
now if f = 5i
5i = i + 40 <--- solve for "i" to see how old Irene was then
If 455 changes to a higher number the mean which is the average should increase to a higher number
Answer: x=2
3x−9x+7−3=−8
Step 1: Simplify both sides of the equation.
3x−9x+7−3=−8
3x+−9x+7+−3=−8
(3x+−9x)+(7+−3)=−8
−6x+4=−8
−6x+4=−8
−6x+4−4=−8−4
−6x=−12
−6x
−6
=
−12
−6
x=2
Answer:
9.3
Step-by-step explanation:
last week she worked 45.6 hours. since 40 hours is the limit for normal working hours, she worked 45.6-40 = 5.6 hours overtime.
this week she worked 9.7+8.3+8+9.1+8.6 hours = 43.7 hours.
she worked therefore 43.7-40 = 3.7 hours overtime.
so, in total of the two weeks, she worked 5.6+3.7 = 9.3 hours overtime.