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Arlecino [84]
3 years ago
5

Can someone please help me?

Mathematics
1 answer:
Zolol [24]3 years ago
7 0

Answer: I think a

Step-by-step explanation:

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What is 6,007,200 in standard form
Orlov [11]

(6,000,000) (7000) (200)

6 0
3 years ago
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed i
Hunter-Best [27]

Answer:

a)  σ/√n= 1.43 min

c) Margin of error 2.8028min

d) [30.1972; 35.8028]min

e) n=62 customers

Step-by-step explanation:

Hello!

The variable of interest is

X: Time a customer stays at a restaurant. (min)

A sample of 49 lunch customers was taken at a restaurant obtaining

X[bar]= 33 mi

The population standard deviation is known to be δ= 10min

a) and b)

There is no information about the distribution of the population, but we know that if the sample is large enough, n≥30, we can apply the central limit theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

Where μ is the population mean and σ²/n is the population variance of the sampling distribution.

The standard deviation of the mean is the square root of its variance:

√(σ²/n)= σ/√n= 10/√49= 10/7= 1.428≅ 1.43min

c)

The CI for the population mean has the general structure "Point estimator" ± "Margin of error"

Considering that we approximated the sampling distribution to normal and the standard deviation is known, the statistic to use to estimate the population mean is Z= (X[bar]-μ)/(σ/√n)≈N(0;1)

The formula for the interval is:

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

The margin of error of the 95% interval is:

Z_{1-\alpha /2}= Z_{1-0.025}= Z_{0.975}= 1.96

d= Z_{1-\alpha /2}*(σ/√n)= 1.96* 1.43= 2.8028

d)

[X[bar]±Z_{1-\alpha /2}*(σ/√n)]

[33±2.8028]

[30.1972; 35.8028]min

Using a confidence level of 95% you'd expect that the interval [30.1972; 35.8028]min contains the true average of time the customers spend at the restaurant.

e)

Considering the margin of error d=2.5min and the confidence level 95% you have to calculate the corresponding sample size to estimate the population mean. To do so you have to clear the value of n from the expression:

d= Z_{1-\alpha /2}*(σ/√n)

\frac{d}{Z_{1-\alpha /2}}= σ/√n

√n*(\frac{d}{Z_{1-\alpha /2}})= σ

√n= σ* (\frac{Z_{1-\alpha /2}}{d})

n=( σ* (\frac{Z_{1-\alpha /2}}{d}))²

n= (10*\frac{1.96}{2.5})²= 61.47≅ 62 customers

I hope this helps!

3 0
2 years ago
Which inequality is true when G = 3/5 ?
GREYUIT [131]

Answer:

D. 15G > 9

Step-by-step explanation:

Given: G = 3/5

Here we have to check each options and find which is true.

Let's start from A.

G - 1 > 2/5

G > 2/5 + 1

G > 7/5 is not true.

B. -10G > 6

Dividing both sides by -10 , we get

G < -6/10

G < -3/5 Is not true.

C. 1 2/5 + G > 3

Now convert 1 2/5 to improper fraction.

1 2/5 = 7/5

7/5 + G > 3

G > 3 - 7/5

G > (15 - 7)/5

G > 8/5 is not rule.

D. 15G > 9

Dividing both sides by 15, we get

G > 9/15

Now we have to simplify 9/15

G > 3/5 which is true.

Answer: D. 15G > 9

Thank you.

4 0
3 years ago
What's is the answer to this question
Novosadov [1.4K]
The first answer is not a stop. The first answer (A) is correct. I hope this helps!
7 0
3 years ago
Read 2 more answers
Solve the simultaneous equations below. Show your work clearly,
prisoha [69]

Answer:

The solution of the given two equations

  ( x, y) = (0,6)

Step-by-step explanation:

<u><em>Step(i)</em></u>

Given equations are

                  y - 2x = 6  ...(i)

                 y + 2x = 6  ...(ii)

Adding (i) and (ii) equations, we get

          y - 2x + y +2x = 6+6

                2 y = 12

                  y =6

<u><em>Step(ii):-</em></u>

substitute y =6 in equation (i). we get

               y - 2x =6

              6 - 2x =6

              6-6 =2x

               0 = 2 x

               x = 0

The solution of the given two equations

  ( x, y) = (0,6)

6 0
3 years ago
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