3 years ago

Three consecutive integers have a sum of 243

2 answers:

7 0

Three consecutive integers are n, n+1, and n+2 so

n+n+1+n+2=243

3n+3=243

3n=240

n=80

So the integers are 80,81, and 82

amid [387]3 years ago

4 0

First integer: x
second integer: x+1
third integer: x+2
Set up an equation: 3x+3=243
3x=240
x=80
The integers are 80,81,82

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