Jonathan's preschool class has 9 girls and 6 boys. Which proportion can be used to determine the percent, P, of boys in class?
2 answers:
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Answer:
a) 6.68th percentile
b) 617.5 points
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution.
has a pvalue of 0.0668
So this student is in the 6.68th percentile.
b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.
He needs a score of X when Z has a pvalue of 0.75. So X when Z = 0.675.
Question:
James has 14,500g of sand in his sandbox. He brings home another 7,400g of sand from the beach to add to his sandbox. How many kilograms of sand does James have in his sandbox now?
Answer:
The quantity of sandbox James has is 21.9kg
Step-by-step explanation:
Given
Initial quantity of sandbox = 14,500 g
Additional quantity = 7,400 g
Required
Total quantity of sandbox in kg
Tp get the total quantity of sandbox, we simply add in the initial and additional quantity of sandbox together;
This is represented mathematically as follows;
Total = Initial Quantity + Additional Quantity
Total = 14,500 g + 7,400 g
Total = 21,900 g
But the question says the answer should be in kg
1000 g is equivalent to 1 kg
21,900 g will be equivalent to
Hence, the quantity of sandbox James has is 21.9kg