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Natasha2012 [34]
3 years ago
8

explain the benefits of each of the three forms of quadratic equations, standard form, vertex form, and factored form. What do t

hey reveal about the graph or the quadratic?
Mathematics
1 answer:
mamaluj [8]3 years ago
4 0

Answer:

Summary:

Standard form allow us to quickly find the y-intercept.

Vertex form allow us to quickly locate the vertex.

And factored form allows us to quickly determine the roots/zeros.

Step-by-step explanation:

The three forms of quadratics are the standard form, vertex form, and the factored form. Each of them reveals a specific part about the quadratic.

Standard Form:

The standard form of a quadratic is:

ax^2+bx+c

There are only two details that can be conveyed by a quadratic in standard form immediately: (1) the leading coefficient a, and (2) the y-intercept.

The leading coefficient a will tell us if the parabola curves upwards or downwards.

And the constant c will give us the y-intercept.

Vertex Form:

The vertex form of a quadratic is:

a(x-h)^2+k

There are also two details that can be conveyed by a quadratic in vertex form:  (1) the vertex, and (2) the leading coefficient.

The leading coefficient is given by a. Again, this tells us the orientation of the parabola.

And the vertex is given by (h, k).

Hence, in my opinion, vertex form is the best form of a quadratic since it immediately reveals the vertex, the most important aspect of a quadratic.

Factored Form:

The factored form of a quadratic is:

a(x-p)(x-q)

Where p and q are the zeros/roots/solutions of the quadratic.

Again, factored form gives us two details about the quadratic: (1) the leading coefficient, and (2) the zeros.

The zeros tells us when the parabola crosses the x-axis, which can assist in graphing.

Summary:

Therefore, each form of a quadratic equation has its own benefits.

Standard form allow us to find the y-intercept.

Vertex form allow us to quickly locate the vertex.

And factored form allows us to quickly determine the roots/zeros.

Hence, depending on the question, each form can be useful in its own way.

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4. Lydia cut out her initial from a piece<br><br> of construction paper,
Ratling [72]

Answer:

Option A is correct.

10 square centimeters.

Step-by-step explanation:

Complete Question

The complete Question is attached in the first attached image.

Lydia cut out her initial from a piece of construction paper. How many square centimeters of construction paper are used to make Lydia's initial?

A) 10 square centimeters

B) 11 square centimeters

C) 15 square centimeters

D) 22 square centimeters

Solution

From the second attached image, it is evident that we can split the L-shaped figure into two rectangles of dimensions (3 cm by 1 cm) and (7 cm by 1 cm)

The total area of the figure is thus

(3 × 1) + (7 × 1) = 10 cm²

Hope this Helps!!!

3 0
3 years ago
Each question is worth 10 pts, I will do brainliest for the person who does both and follow pls help.
In-s [12.5K]

Answer:

1. 6

2.

pennies = 9

nickels = 5

quaters = 5

dimes = 10

Step-by-step explanation:

1.

18/3 = 6

as we know that there are 18 scoops, and 3 per icecream, we can divide the two to get the number of ice creams

2.

5n

#n = #q; #q = 2#d, this is a simple ratio, you just plug in the variables to get

5n = 5q = 10d = 15 coins

24 - 15 = 9 pennies

pennies = 9

nickels = 5

quaters = 5

dimes = 10

8 0
2 years ago
F divided by 2 = 5/8
Vedmedyk [2.9K]

Answer:

1.25

Step-by-step explanation:

5 0
3 years ago
Write a polynomial of degree 3 that satisfies each of the given conditions.
shutvik [7]

Answer:

https://www.jacksonsd.org/cms/lib/NJ01912744/Centricity/Domain/504/BI%207-8.pdf

Step-by-step explanation:

the link to help you with the answers

5 0
3 years ago
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
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