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Rus_ich [418]
3 years ago
15

Name a diameter for the circle. •DG •EF •DH •FH

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0
It would be FH
A diameter is basically the length of the line through the centre that touches 2 points on a circles edges
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How is the expression (5 + y) ⋅ 8 described by its factors and terms? It has two factors and the factor (5 + y) has one term. It
blsea [12.9K]

Answer:

There are 2 factors

Step-by-step explanation:

7 0
3 years ago
Write the polynomial in factored form as a product of linear factors f(r)=r^3-9r^2+17r-9
adelina 88 [10]

Answer:

  f(r) = (x -1)(x -4+√7)(x -4-√7)

Step-by-step explanation:

The signs of the terms are + - + -. There are 3 changes in sign, so Descartes' rule of signs tells you there are 3 or 1 positive real roots.

The rational roots, if any, will be factors of 9, the constant term. The sum of coefficients is 1 -9 +17 -9 = 0, so you know that r=1 is one solution to f(r) = 0. That means (r -1) is a factor of the function.

Using polynomial long division, synthetic division (2nd attachment), or other means, you can find the remaining quadratic factor to be r^2 -8r +9. The roots of this can be found by various means, including completing the square:

  r^2 -8r +9 = (r^2 -8r +16) +9 -16 = (r -4)^2 -7

This is zero when ...

  (r -4)^2 = 7

  r -4 = ±√7

  r = 4±√7

Now, we know the zeros are {1, 4+√7, 4-√7), so we can write the linear factorization as ...

  f(r) = (r -1)(r -4 -√7)(r -4 +√7)

_____

<em>Comment on the graph</em>

I like to find the roots of higher-degree polynomials using a graphing calculator. The red curve is the cubic. Its only rational root is r=1. By dividing the function by the known factor, we have a quadratic. The graphing calculator shows its vertex, so we know immediately what the vertex form of the quadratic factor is. The linear factors are easily found from that, as we show above. (This is the "other means" we used to find the quadratic roots.)

7 0
3 years ago
Help please
Arisa [49]

Answer:

E. Leela Chitnis

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Is anyone able to see if there is a counterexample for the following argument in logic?
Colt1911 [192]

if A=B

B=/=C

No A=C

All C are not A

6 0
3 years ago
Can someone help me do this i need helpppp
Vedmedyk [2.9K]
AngleA= angle D
5x+2=87
5x=85
X=17

180-87-42=51

Angle C= angle F
3y=51
Y=17
3 0
3 years ago
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