To solve this multiply through by the LCM of 4 and 6, which is 12:-
12 * x/4 - 12 * x/6 = 1*12
3x - 2x = 12
x = 12 answer
Answer: 3
Step-by-step explanation:
cause I said so :) mark brainliest pls
Answer:
x < -6
Step-by-step explanation:
X/4 < -1.5
Multiply each side by 4
X/4*4 < -1.5*4
x < -6
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
16+24xy+9y2 that is what I got
