The volume of the right rectangular prism is 6656 cubic inches, If the rectangular prism have a length of 32", width of 52" and height of 4".
Step-by-step explanation:
The given is,
A right rectangular prism
Let, l - Length of the right rectangular prism
w - Width of the right rectangular prism
h - Height of the right rectangular prism
Step:1
From given,
l - 32 inches
w - 52 inches
h - 4 inches
Step:2
Formula for Volume of the Right rectangular prism,
.............................................(1)
Substitute the values of w, h and l in Eqn (1)
= ( 52 × 4 × 32 )
V = 6656 
Result:
Thus the volume of the right rectangular prism is 6656 cubic inches, for the given dimensions of an right rectangular prism.
Answer: X = (d-b) / (a-c)
This way this worded is weird but I think I got it
Step-by-step explanation:
Subtract B from both sides
ax = cx +d -b
Then subtract CX from both sides
ax -cx =d-b
Distributive Property
x(a-c) =d-b
Divide both sides by a-c
X = (d-b) / (a-c)
1) the types of number are the negative integers (e.g √-1 √-3 <span>√-5 are not defined)
2) the answer is No, proof: 2x</span>√-1 is not defined because <span>√-1 doesn't exist
3) the answer is No, proof: </span>√-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square <span>3 + √-1, I use the method of complex number
i²= -1, it implies i= </span>√-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number
Given:
15. 
17. 
19. 
To find:
The values of the given logarithms by using the properties of logarithms.
Solution:
15. We have,
Using property of logarithms, we get
![[\because \log_aa=1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%3D1%5D)
Therefore, the value of is 1.
17. We have,
Using properties of logarithms, we get
![[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D-%5Clog_a%5Cdfrac%7Bn%7D%7Bm%7D%5D)
Therefore, the value of is -1.
19. We have,
Using property of logarithms, we get
![[\because a^{\log_ax}=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B%5Clog_ax%7D%3Dx%5D)
Therefore, the value of is 100.
800000000+40000000+5000000+300000+30000+3000+100+20+9
