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AURORKA [14]
3 years ago
14

True or False? Each point on the perpendicular bisector of a segment is equidistant from the endpoints of the segment.

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0
True

The Perpendicular Bisector Theorem states, If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment
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Help quickly please!!!​
Helen [10]

Answer:

1) 0.008

2) 0.22

3) 0.01

4) 0.2

5) 0.1%

6) 758%

7) 3%

8) 0.7%

9) 9.19

10) 2.5

11) 1

12) 8.613

13) 4

14) 6.75

15) 15.45

16) 42.1

17) 5

18) Whatever number you can only see the 1 of, because it didn't make it into the picture.

Hope this helps!

3 0
4 years ago
On a​ map, 1 inch equals 9.2 miles. Two houses are 1.5 inches apart on the map. What is the actual distance between the​ houses?
JulsSmile [24]

Answer:

The distance between the two houses is <u>13.8 miles</u>.

Step-by-step explanation:

Half of 9.2 is 4.6, so I added the two numbers together because it would be 1.5 inches and the answer is 13.8 miles.

4 0
3 years ago
Somebody hop on my a chat 557+50
dangina [55]

Answer:

607

Step-by-step explanation:

557+50=607

5 0
3 years ago
43 ones times 3 tens = how many tens
romanna [79]
Well 43 ones times 3 tens is basically 43 times 30 which is 1,290
then divide that by ten to get how many tens and you will get 129 tens
hope this helps
3 0
4 years ago
Read 2 more answers
Pls help!!!!!!!!!!!!!!
Arisa [49]

Answer:

C) √221 units

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-7, 7)

Point (7, 2)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    d = \sqrt{(7+7)^2+(2-7)^2}
  2. Add/Subtract:                       d = \sqrt{(14)^2+(-5)^2}
  3. Exponents:                           d = \sqrt{196+25}
  4. Add:                                      d = \sqrt{221}
5 0
3 years ago
Read 2 more answers
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