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solong [7]
2 years ago
10

Graph the equation 36x^2 + 16y^2 = 576 on a graphing calculator. Identify the conic section. Then identify the center and interc

epts for circles and ellipses, or the vertices and direction that the graph opens for parabolas and hyperbolas.

Mathematics
1 answer:
trasher [3.6K]2 years ago
5 0

Answer:

If we use a graphing tool or a calculator, we can easily plot the equation provided.

Please see the attached images, where we can find the center of the ellipse, the intercepts and more information about the graph.

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Can you help me please !
Bezzdna [24]

Answer:

Square root of 7 minus 2 equals x.

Step-by-step explanation:

X is irrational soooo

4 0
3 years ago
Solve the compound inequality 3x + 4 ≤ 7
Ierofanga [76]

Answer:

x ≤ 1

Step-by-step explanation:

3x+4≤ 7

3x + 4 - 4 ≤ 7 - 4

3x≤3

x ≤ 1

3 0
3 years ago
Judy Clark went to Reel Bank. She borrowed $7,800 at a rate of 6 1/2%. The date of the loan was September 2. Judy hoped to repay
abruzzese [7]

Answer:

$7995.85

Step-by-step explanation:

We will use simple interest formula to solve our given problem.

A=P(1+rt), where,

A = Amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

r=6.5\%=\frac{6.5}{100}=0.065

t=\text{141 days}=\frac{141}{365}\text{ year}

A=\$78001+0.065\times \frac{141}{365})

A=\$7800(1+0.065\times 0.38630136986)

A=\$7800(1+0.025109589041)

A=\$7800(1.025109589041)

A=\$7995.85479

A\approx \$7995.85

Therefore, Judy will will pay back on January 20: <u>$7995.85</u>.

8 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 180 lb and each bo
s344n2d4d5 [400]
It would be 12 boxes
3 0
3 years ago
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