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Alona [7]
2 years ago
7

what apparatus should be used to measure the surface area to volume ratio of a potato cylinder? with explanation

Biology
1 answer:
n200080 [17]2 years ago
6 0

Answer: Measuring scale/ruler.

Explanation: As it's a cylinder you would just need to find the diameter and the height. You can then use the formula V = πr²h and TSA =  2πr² + 2πrh.

Put the values in the form "surface area : volume" and you get your desired output.

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A current Procedural Terminology (CPT) code is a medical code that describes or emphasize precisely on the service a health care provider has performed for a patient. CPT describes medical, surgical, and diagnostic services and it also help to pass uniform information about medical services among health workers and patients.






6 0
3 years ago
Which of the following are NOT energy reserves?
vladimir2022 [97]

The correct answer is C) carboxysomes

Carboxysomes are polyhedral inclusion bodies that contain enzyme ribulose- 1,5-bisphosphate carboxylase/oxygenase (RuBisCO). This is responsible for the fixation of carbon dioxide in cyanobacteria. Carboxysomes have evolved as a consequence of the increase in oxygen concentration in the ancient atmosphere.

Thus, <em>carboxysomes are not energy reserves</em>, unlike another offered answers.

3 0
3 years ago
Practice Problem
Nadya [2.5K]

Answer:

0,45 is the population I guess

8 0
3 years ago
True or False:
slamgirl [31]
“His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.”
4 0
2 years ago
Read 2 more answers
The pKa for the side chain of histidine is 6.0. What is the ratio of the deprotonated imidazole side chain to the protonated sid
Solnce55 [7]

Answer:

When the pKa is 6.0, we can determine the fraction of protonated H is by:

pH = pKa + log [A]/[HA]

Where

A = Deprotonated imidazole side

HA = Protonated side

Given, pH = 5.0

5 = 6 + log [A]/[HA]

log [A]/[HA] = -1 (take antilog of both side)

[A]/[HA] = 0.1

The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 0.1

Given, pH = 7.5

7.5 = 6 + log [A]/[HA]

log [A]/[HA] = 1.5 (take antilog of both sides)

[A]/[HA] = 31.62

The ratio of the deprotonated imidazole side chain to the protonated side chain at pH 5.0 = 31.62

7 0
3 years ago
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