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3 years ago

How many moles are equal to 157.8g of CaCl2?

1 answer:

4 0

K: 157.8g CaCl2
U: ? mol CaCl2

1Ca = 1(40.08) = 40.08
2 Cl = 2(35.45) =+ 70.90
110.98

157.8g CaCl2 1 mol CaCl2

1 mol CaCl2 110.98g CaCl2

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Karolina [17]

Answer:

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Explanation:

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3 years ago

In a paragraph, explain what the story of the Gadarene demoniac teaches us about our life in Christ.

GarryVolchara [31]

Answer:

Just like the previously possessed man told people about his new life in Christ, we, too, should share about our new life in Christ.

Explanation:

The story of the demonaic is about a possessed man whose unclean spirits were sent out by Jesus. The spirits were sent into the pigs of the people who raised them to sell for profit (some of which were the Jew's pigs,) and they ran off the cliff and drowned. The owners of these pigs knew that Jesus did it to save the man but still were mad and wanted nothing to do with Jesus. They told Him to leave even though He saved the possessed man who they had previously tried to help. The man wanted to travel with Jesus, but He told the healed man to depart from Him and go to the people and share his story and how Jesus helped Him, and he obeyed. Just like the previously possessed man told people about his new life in Christ, we, too, should share about our new life in Christ.

Hope this helps. Don't hate me if it's wrong but this is what I found.

6 0

2 years ago

You have 41.6 g of O2 gas in a container with twice the volume as one with CO2 gas in another container. The pressure and temper

prisoha [69]

Answer:

The mass of carbon dioxide is 28.6 grams

Explanation:

Step 1: Data given

Mass of O2 = 41.6 grams

Volume of the O2 container = 2V

Volume of the CO2 container = V

Pressure and temperature are the same

Step 2: Ideal gas law

The ideal gas law = p*V=nRT

For O2: p*2V = n(O2)*R*T

For CO2: p*V = n(CO2)*R*T

n(O2)*R*T / P*2V = n(CO2)*R*T / P*V

Since P, R and T are contstant, we can simplify this to:

n(O2)/2 = n(CO2)

Step 3: Calculate moles of O2

Moles O2 = mass O2/ Molar mass O2

Moles O2 = 41.6 grams / 32 g/mol

Moles O2 = 1.3 mol O2

The number of moles CO2 = 0.65 mol

Mass of CO2 = Moles CO2 * Molar Mass CO2

Mass of CO2 = 0.65 mol * 44.01 g/mol

Mass of CO2 = 28.6 grams

The mass of carbon dioxide is 28.6 grams

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4 years ago

Which of the following chemical reactions is an oxidation-reduction reaction? Fe2O3 + 3CO yields 2Fe + 3CO2 MgSO4 + 2KIyields K2

Elodia [21]

I hope I am right on this, but the answer is
Fe₂O₃ + 3CO --> 2Fe + 3CO₃

5 0

3 years ago

Read 2 more answers

A gas occupies 18.7 L at standard temperature. What is its volume at 200.5 °C

nexus9112 [7]

Answer:

32.4 L

Explanation:

Note 1:

The Standard Temperature and Pressure (STP) is defined by IUPAC as air at 0 gradius Celcius and 1 bar.

Note 2:

The Ideal Gas Law is used for solving this problem.

......

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0

4 years ago