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3 years ago

Watch the animation and identify the correct conditions for forming a hydrogen bond.

Chemistry

1 answer:

torisob [31]3 years ago

8 0

Answer:

options B,C and E are correct conditions for forming hydrogen bonds.

Explanation:

In order for particles to stick together or shows certain characteristics, there must be a bond of attractions that is making them to be able to stay together. Some of these attractions are strong while some are weak. The kind of attraction that is being considered in this question is the hydrogen bonding which is considered as part of the weak forces of attractions.

In order for hydrogen bonds to occur, there must be hydrogen atoms [option B is correct] and a much more electronegative elements such as oxygen, Fluorine and Nitrogen. Hence, option C is correct.

Since the Fluorine or oxygen or nitrogen have much more electronegative properties than hydrogen, it causes a partial negative charge on Fluorine or oxygen or nitrogen and a partial positive charge on the Hydrogen. Thus, option E is correct.

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How many atoms are present in 0.0350 mol of barium phosphate

lesya692 [45]

There are 3 Barium, 2 Phosphorus and 8 Oxygen in Barium Phosphate (Ba3(PO4)2, making 13 units. Multiply 0.0350 mol given by 13 and then you get 0.455 mol. Since they want atoms, multiply 0.455 by Avogadro's number (0.455 x 6.023 x 1023) and you get 2.74 atoms of barium phosphate.

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3 years ago

How many moles are there in 7.24 grams of calcium carbonate? With work shown

balu736 [363]

Answer:

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2 years ago

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What is the temperature of 0.55 mol of gas at a pressure of 1.5 atm and a volume of 12.6 L ?

Taya2010 [7]

Answer:

The temperature is 419,1 K

Explanation:

We use the formula PV=nRT T=PV/nR

T=1,5 atm x 12,6 L/0,55 mol x 0,082 l atm/K mol

T= 419,0687361 K

3 0

3 years ago

A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t

drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

$p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t}$ (1)

where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s)

(a) We can calculate the energy (ΔU) using equation (1):

$\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J$

(b) The work is related to pressure and volume by:

$\Delta W = -p \Delta V$

where p: pressure and ΔV: change in volume = V final - V initial

$\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J$

(c) By the definition of Energy, we can calculate q:

$\Delta U = \Delta W + \Delta q$

where Δq: is the heat transfer

$\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J$

I hope it helps you!

6 0

3 years ago

The SN1 reaction yields Entry field with incorrect answer two (number) products. This is because ______________________. Entry f

vagabundo [1.1K]

Answer:

Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule

Explanation:

An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.

However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.

The attacking nucleophile in this case may be water or CH3OH

4 0

3 years ago