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3 years ago

Watch the animation and identify the correct conditions for forming a hydrogen bond.

Chemistry

1 answer:

torisob [31]3 years ago

8 0

Answer:

options B,C and E are correct conditions for forming hydrogen bonds.

Explanation:

In order for particles to stick together or shows certain characteristics, there must be a bond of attractions that is making them to be able to stay together. Some of these attractions are strong while some are weak. The kind of attraction that is being considered in this question is the hydrogen bonding which is considered as part of the weak forces of attractions.

In order for hydrogen bonds to occur, there must be hydrogen atoms [option B is correct] and a much more electronegative elements such as oxygen, Fluorine and Nitrogen. Hence, option C is correct.

Since the Fluorine or oxygen or nitrogen have much more electronegative properties than hydrogen, it causes a partial negative charge on Fluorine or oxygen or nitrogen and a partial positive charge on the Hydrogen. Thus, option E is correct.

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Serotonin acts as a weak base and has a pkb = 3. 84. what is the ph of a solution made by adding 0. 025 m of serotonin in water?

Zarrin [17]

Serotonin acts as a weak base and has a pkb = 3. 84. The ph of a solution made by adding 0. 025 m of serotonin in water is 2.4.

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1 year ago

A voltaic cell is based on the reduction of ag (aq) to ag(s) and the oxidation of sn(s) to sn2 (aq).

Annette [7]

Half-reaction for the cell's anode is given below:

Anode : $\\Sn(s) \rightarrow Sn^{2+} (aq) +2e^{-}$

The anode is defined as the electrode at which electrons leave the cell and oxidation occurs, and the cathode as the electrode at which electrons enter the cell and reduction occurs. The anode is usually the positive side.

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brainly.com/question/4052514

Your given question is quite incomplete here is complete question.

A voltaic cell is based on the reduction of _ Agt(aq) to Ag(s) and the oxidation of Sn(s) to Sn2+(aql) : Part 1 Include the phases of all species in the chemical equation: (aqh Anode: Sn(s) Sn?+ (aq)

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2 years ago

Highlight the basic points in Lewis and Langmuir theory of electrovalency

ankoles [38]

The correct answer for the question that is being presented above is this one: "Electrovalency is characterized with the transferring of one or more electrons from one atom to another together with the formation of ions and as well as the number of positive and negative charges.

The Lewis and Langmuir theory of electrovalency (and as well as Kossel's) is dealing with Ionic bonds.

Lewis: electron-pair sharing, octet rule, Lewis Symbols or StructureLangmuir: introduced term "covalent" bond, and popularized Lewis's ideas

<span>The Lewis-Langmuir electron-pair or covalent bond is referred as the homopolar bond, where the complete transfer of electrons give rise to ionic, or electrovalent bond (1) through attraction of opposite charges.</span>

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3 years ago

According to the selection, what is the main weakness of the tortoise?<br>

Agata [3.3K]

Answer:

Nose

Explanation:

Because every time I touch it's nose, it will hide itself into the shell faster than other places

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3 years ago

Suppose that 25.0 mL of 0.440 M sodium chloride is added to 25.0 mL of 0.320 M silver nitrate. How many moles of silver chloride

d1i1m1o1n [39]

The number of moles of silver chloride that will precipitate is 0.008 mole

From the question,

We are to determine the number of moles of silver chloride that will precipitate

First,

We will write a balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

NaCl + AgNO₃ → AgCl + NaNO₃

This means

1 mole of sodium chloride reacts with 1 mole of silver nitrate to produce 1 mole of silver chloride and 1 mole of sodium nitrate

Now, we will determine the number of moles of each reactant present

For sodium chloride (NaCl)

Concentration = 0.440 M

Volume = 25.0 mL = 0.025 L

Using the formula

Number of moles = Concentration × Volume

∴ Number of moles of NaCl present = 0.440 × 0.025

Number of moles of NaCl present = 0.011 mole

For silver nitrate (NaNO₃)

Concentration = 0.320 M

Volume = 25.0 mL = 0.025 L

∴ Number of moles of NaNO₃ present = 0.320 × 0.025

Number of moles of NaNO₃ present = 0.008 mole

From the balanced chemical equation,

1 mole of sodium chloride reacts with 1 mole of silver nitrate to produce 1 mole of silver chloride

Then,

0.008 mole of sodium chloride will react with the 0.008 mole of silver nitrate to produce 0.008 mole of silver chloride

∴ 0.008 mole of silver chloride will be produced

Hence, the number of moles of silver chloride that will precipitate is 0.008 mole

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2 years ago