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Anit [1.1K]
3 years ago
12

Which of the following chemical reactions is an oxidation-reduction reaction? Fe2O3 + 3CO yields 2Fe + 3CO2 MgSO4 + 2KIyields K2

SO4 + MgI2 NaNO3 + KCl yields KNO3 + NaCl Cu(NO3)2 + 2HBryields CuBr2 + 2HNO3
Chemistry
2 answers:
Elodia [21]3 years ago
5 0
I hope I am right on this, but the answer is
Fe₂O₃ + 3CO --> 2Fe + 3CO₃
alexgriva [62]3 years ago
5 0

Answer : The reaction that is an example of oxidation reduction reaction is "Fe2O3 + 3CO yields 2Fe + 3CO2 "

Explanation :

The oxidation reduction reaction is the one in which one of the elements undergo oxidation and the other undergoes reduction.

The oxidation number of the element that undergoes oxidation increases .

The oxidation number of the element that undergoes reduction decreases.

Let us find out which of these reactions show an increase and decrease in oxidation numbers.

Fe_{2}O_{3}+3 CO\rightarrow 2Fe + 3CO2

Let us find out the oxidation numbers of the elements involved in this reaction.

The standard oxidation state of O is -2

The overall charge on the compound Fe₂O₃ is 0.

Let us set up an equation to find oxidation number of Fe in Fe₂O₃.

2 ( oxidation number of Fe) + 3 ( Oxidation number of O) = Overall charge

2 ( oxidation number of Fe) + 3 ( -2) = 0

2 (oxidation number of Fe) - 6 = 0

oxidation number of Fe = 6/2 = +3

Oxidation number of Fe on reactant side is +3.

On product side Fe is present in its standard state. Therefore its oxidation number is 0.

Oxidation number of Fe on product side is 0.

Oxidation number of Fe changes from +3 to 0 which shows a decrease.

That means Fe undergoes reduction.

Let is find oxidation number of C on both the sides.

Oxidation number of C in CO is

oxidation number of C + (-2) = 0

oxidation number of C = +2

Oxidation number of C on reactant side is +2

Oxidation number of C in CO₂ is

Oxidation number of C + 2 x (-2) = 0

Oxidation number of C = +4

Oxidation number of C on product side is +4

Oxidation number for C changes from +2 to +4, which shows an increase.

Therefore C undergoes oxidation.

We can say that in the above reaction, one element ( Fe) undergoes reduction and the other (C) undergoes oxidation. This is an example of oxidation-reduction reaction.

Hence the correct option is "Fe2O3 + 3CO yields 2Fe + 3CO2 "

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Answer:

The total energy to break all the bonds in 1 mole of 1-propanol, C₃H₈O, is 4411 kJ/mol

Explanation:

We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;

CH₃CH₂CH₂OH which gives

CH₃-CH₂-CH₂-OH

Hence, the total number of bonds are;

C-H Bonds = 3 + 2 + 2 = 7

C-O Bonds = 1

O-H Bond = 1

C-C Bonds = 2

The bond energies are as follows;

C-H Bonds = 413 kJ/mol

C-O Bonds = 358 kJ/mol

O-H Bond = 468 kJ/mol

C-C Bonds = 347 kJ/mol

Energy required to break the bonds in 1-propanol is therefore;

C-H Bonds = 413 kJ/mol × 7 = 2,891 kJ/mol

C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol

O-H Bond = 468 kJ/mol × 1 = 468 kJ/mol

C-C Bonds = 347 kJ/mol × 2 = 694 kJ/mol

The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.

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Answer:

A. The color change from blue to green happens in nature.

Explanation:

The color change is an indicator of a chemical reaction that has occurred. Although color changes are not necessarily good diagnostic tool to measure if a chemical reaction has occurred or not.

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Answer:

Q = 768.47 J

Explanation:

Given that,

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The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

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Chemical species which are capable of donating electron pairs or accepting protons are called Lewis base.

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For a chemical species to behave as Lewis base, they must have:

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For example, NH3 and OH, both N and O have lone pairs of electrons, hence behave as Lewis base.

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