Logical memory is the address space, assigned to a logical partition, that the operating system perceives as its main storage.
Answer:
It's not good in reality to touch the Chromebook's screen with your finger, a pencil, a pen or anything like your thumb. They might start looking blurred or if you touch them very hard then they might crack as well. If this happens, report to the authorized store immediately, and if warranty prevails you will get it repaired at no extra cost. However, take this as a warning, and keep in mind the precautions mentioned in the explanation.
Explanation:
Never put extra pressure on the Chromebook screen, and even when it is not open.
Always store it in a closed position.
Always keep the things that can put pressure away from your Chromebook.
Never poke your screen with something that put a mark or a kind of scratch on the surface of the screen.
Never ever, place something on the keyboard like pens, disks or pencils prior to shutting the lid.
The climax. The climax is when the story peaks and has the most suspense. The story falls closer to it's end after the climax.
Answer:Following is the c++ code for the problem:
#include <iostream>
using namespace std;
int main() {
int number;
cout<<"Enter the number"<<endl;
cin>>number;
int i=0,c=0,odd[500];
while(i<=number)//loop for printing the numbers form 0 to number.
{
cout<<i<<" ";
if(i%2!=0)// storing in the odd array if the number is odd.
{
odd[c++]=i;//storing odd numbers..
}
i++;
}
cout<<endl;
i=0;
cout<<"The odd numbers are "<<endl;
while(i<c)//loop to print the odd numbers.
{
cout<<odd[i]<<" ";
i++;
}
cout<<endl<<"The prime numbers are "<<endl;
i=0;
int sum=0;
while(i<c)//loop to print the prime numbers..
{
int div=2;
while(div<odd[i])
{
if(odd[i]%div==0)
break;
div++;
}
if(div==odd[i])
{
cout<<odd[i]<<" ";
sum+=odd[i];//updating the sum..
}
i++;
}
cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..
return 0;
}
Output :
Enter the number
49
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
The odd numbers are
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
The prime numbers are
3 5 7 11 13 17 19 23 29 31 37 41 43 47
The sum of odd prime numbers is 326
.
Explanation:
First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.
Answer:
Check the explanation
Explanation:
Going by the question above,there are 2 routers in a sequence amid Host A and Host B and using store-and-forward routing.
So that time would conprise of both propagation delay and transmission time
Propagation delay is nothing but the time taken for traveling.
Transmission delay is the amount of delay time from the beginning to end of transmission)
Now,
Propagation delay = distance traveled / speed of propagation
= 161200 / 2.7 *108 = 59703703.70 * 10-8 mili sec
Transmission delay:
= packet size / bandwidth
= 4 / (9.1 * 1024) = 4.2925 * 10-1 mili sec
Let us assume routers have zero (0) processing time
total time = Transmission delay by host A + Transmssion delay by router1 + Transmssion delay by router2 + propagation time
= 3 * ( 4.2925 * 10-1 ) + (59703703.70 * 10-8)
= 1.28775 + 0.5970370370 ms
= 1.884787 ms
