f(x) = x² + 1, x > 0
y = x² + 1
x = y² + 1
x - 1 = y²
√x - 1 = y
√x - 1 = f(x), x > 1
Answer:
B,C,E your welcome
Explanation: i just took the test
Answer:
The solution code is written in Python 3
- digits = input("Enter 9 digits: ")
-
- multiplier = 1
- total = 0
-
- for x in digits:
- total += int(x) * multiplier
- multiplier += 1
-
- checksum = total % 11
-
- if(checksum == 10):
- print(digits + "X")
- else:
- print(digits + str(checksum))
Explanation:
Firstly, use input function to get user input for 9 digits (Line 1)
Next we can use a for-loop to estimate the summation (d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5+ d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9) ( Line 6-8)
Then only apply % operator to get the remainder of total and get the checksum (Line 10)
Next create if and else statement to print the digits string joined with X if checksum is 10 else join digits string with checksum value (Line 12 -15)
Like when a seed drops on the ground, and a bee come to take some honey. It sticks to the bee and where the bee goes, the bee will rub it off and the seed will start to grow.
