Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
I think the answer is 20.25 because when solving for the area of a triangle you do 1/2 base times height and so the equation would be
1/2(9)(4.5)
you would start by doing 9(4.5) which equals 40.5
then you would divide by 1/2 which equals 20.25
hope this helps:)
Answer:
105/330 = 21/66 = 7/22
7/22 is the answer I think
Step-by-step explanation:
n(U) = 330
n(A) = 85
n(B) = 200
n(A n B) = 60
Now,
n(A U B) = n(A) + n(B) - n(A n B)
or, n(A U B) = 85 + 200 - 60
or, n(A U B) = 285 - 60 = 225
Now,
n(A U B) compliment = n(U) - n(A U B)
n(A U B) compliment = 330 - 225
so, n(A U B) compliment = 105
Now,
probability = 105/330
Answer:
can you make the picture bigger and show the all of the answers, if yes i believe i can do the problem thank you
Step-by-step explanation:
