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jarptica [38.1K]
3 years ago
13

0.26 simplest form as a fraction or mixed number

Mathematics
1 answer:
NeX [460]3 years ago
8 0

0.26 has the same meaning as 26/100. That can't be reduced very far, but it can be reduced.

0.26 = 26/100 Divide top and bottom by 2

13/50 That's as far down as we can go.

Note: any decimal with 2 digits can always be put over 100 and reduced if possible.

0.33 = 33 / 100

0.16 = 16 / 100 = 4/25 (Divide by 4) which is all you can do.

0.01 = 1 /100

Three digits would require 1000 in the denominator if the number is between -1 and 1

0.112 = 112/1000 = 56/500 = 28/250 = 14/125

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Retail price is the price an item is selling for in store so I would say yes unless its on sale.
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What are the solutions of |3x + 2| >9?​
frosja888 [35]

Answer

-11/3>x>7/3

Step-by-step explanation:

|3*7/3+2|=9

|7+2|=9

|9|=9

9=9

therefore, x must be > 7/3

|3*-11/3+2|=9

|-11+2|=9

|-9|=9

9=9

therefore, x must be < -11/3

8 0
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A square has side lengths of 9, which of the following is a correct formula for finding the area of a square? Select all that ap
Tasya [4]
L • w = a
9 • 9 = 81
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3 0
3 years ago
Read 2 more answers
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
If there are 13 inches of snow in 8 hours how many inches in are there 1 hour
Ugo [173]

Here is 3 different ways to write how much snow fell in one hour

  1. Exact form (improper fraction) form: 13/8
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All u need to do is divide 13 by 8

6 0
3 years ago
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