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MArishka [77]
4 years ago
5

If a line crosses the y-axis at (0,1) and has a slope of 4/5, what is the equation of the line ?

Mathematics
1 answer:
stepladder [879]4 years ago
6 0
The slope intercept form of a line is y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).  We are given that the slope is 4/5 and the point (0,1) so we know m=4/5 and b=1 so:

y=4x/5+1  now to rearrange into standard form ax+by=c

y=(4x+5)/5

5y=4x+5

5y-4x=5

So the answer is D.

However, by convention, in standard form, the equation is usually expressed with a positive coefficient for x.

5y-4x=5 SHOULD be expresses so the x has a positive coefficient, divide both sides by -1 and you have the technically correct form:

4x-5y=-5

Apparently whomever/whatever posed this question to you was unaware of this convention :P
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3 years ago
Mr. blue's first year salary is $30,000 and it doubles each year. what is the explicit rule for the sequence in simplified form?
trasher [3.6K]

Answer: Explicit Rule: a_n=30,000 • 2^n-1

Recursive Rule: a_n = 2a_n-1; a_1 = 30,000

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8 0
2 years ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
4 years ago
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