We have the following points and their coordinates:
We must compute the distance ST between them.
The distance ST between the two points is given by:
![ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},](https://tex.z-dn.net/?f=ST%3D%5Csqrt%5B%5D%7B%28x_S-x_T%29%5E2%2B%28y_S-y_T%29%5E2_%7B%7D%7D%2C)
where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.
Replacing the coordinates of the points in the formula above, we find that:
![\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ST%3D%5Csqrt%5B%5D%7B%28-3_%7B%7D-%28-2%29_%7B%7D%29%5E2%2B%2810_%7B%7D-3_%7B%7D%29%5E2_%7B%7D%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B1%5E2%2B7%5E2%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B50%7D%5Ctext%7B.%7D%20%5Cend%7Bgathered%7D)
Answer: ST = √50
Answer:
in order for your fraction to equal 3 you need to have 9/3 which will equal 3. so what minus 1 will get you 9? 10 will. x=10
10-1/3
9/3
3=3
2x + 5y = -3 ⇒ 2x + 5y = -3
1x + 8y = 4 ⇒ <u>2x + 16y = 8
</u> -<u>11y</u> = <u>-11 </u>
-11 -11
y = 1
2x + 5(1) = -3
2x + 5 = -3
<u> -5 -5</u>
<u>2x</u> = <u>-8</u>
2 2
x = -4
(x, y) = (-4, 1)
2x + 1y = 7 ⇒ 2x + 1y = 7
1x - 2y = -14 ⇒ <u>2x - 4y = -28</u>
<u>5y</u> = <u>35</u>
5 5
y = 7
2x + 7 = 7
<u> -7 -7</u>
<u>2x</u> = <u>0</u>
2 2
x = 0
(x, y) = (0, 7)
I think 4
Step-by-step explanation:
Doug's bar is 50 km away from Ben's bar. let me know if I need to explain.
