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3 years ago

8

Without looking it up- what is -2317 - (-5294)?

2 answers:

vovangra [49]3 years ago

4 0

Answer:

=2977

Step-by-step explanation:

-2317 - (-5294)

-2317 + 5294

2977

Dafna1 [17]3 years ago

3 0

2977
-2317-(-5294)=
2977

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andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

1 year ago

Use the equation A = bh to calculate the height of a parallelogram with an area of 36 square inches and a base of 9 inches

hichkok12 [17]

Answer:

4 inches

Step-by-step explanation:

A = b x h

A = 36

b = 9

36 = 9 x h

4 = h

height = 4 inches

6 0

2 years ago

Solve this equation:<br> X – 8<br> 6<br> = 4.5<br> Your answer

barxatty [35]

Answer:

Multiply by 6 on both sides

X-8 = 27

add 8 to both sides

X = 35

Hope this helps

Double-checking

35 - 8 = 27

27 / 6 = 4.5

35 = X is the answer

Hope this helps

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

16x^7 - 8x^3 / 4x^3

Sunny_sXe [5.5K]

Answer:

4x^4-2

Step-by-step explanation:

$\dfrac{16x^7-8x^3}{4x^3}= \\\\\\\dfrac{4x^3(4x^4-2)}{4x^3}= \\\\\\4x^4-2$

Hope this helps!

8 0

3 years ago

Read 2 more answers

stiv31 [10]

Answer:

A

Step-by-step explanation:

Hello There!

The y value of ABC was subtracted by 7 to get to the figure A'B'C'

So the rule for the given transformation would be

(x,y) ---> (x,y-7)

5 0

3 years ago