6x³y + 6xy − 12x² − 12 = 6(xy-2) * (x²+1)
(x²+1) is a factor of 6x³y + 6xy − 12x² − 12
Answer:
Quadrants I and IV
Step-by-step explanation:
When we graph y^2 = x - 4, we see that it is on the x axis, and goes up into Quadrant I, and down into Quadrant IV
Answer:
<h2>NONE OF THEM</h2>
Step-by-step explanation:
From the graph,
y and x intercepts are 
and approximately 
respectively
for A, C and D : 
x intercept the value of y=0, and y intercept x=0.
x and y intercepts are 
and approximately respectively
for B: 
x and y intercepts are 
and approximately respectively
Therefore x and y intercepts for the lines 
and 
they are not equal to the x and y intercepts of the given graph
10+(-2)=10-2
Therefore 10-2=8
There are no real roots for a negative number, so -81 has no real roots, if the number is 81 however, then the tow roots are 9
