The slope-intercept form: y = mx + b
m - slope
b - y-intercept
We have y = 4x + 3
m = 4 - slope
3 - y-intercept
4 units up and 1 unit right
Answer:
A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.
B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.
Step-by-step explanation:
f(x) = 12x^2 + 5x - 2.
Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).
To find the roots of f(x), set f(x) = 0. Therefore:
12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:
12x^2 + 8x - 3x - 2 = 0.
4x(3x + 2) -1(3x+2) = 0.
(4x-1)(3x+2) = 0.
4x-1 = 0 or 3x+2 = 0.
x = 1/4 or x = -2/3.
It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!
Answer:
B
Step-by-step explanation:
These numbers form an addition and subtraction, fact family.
4, 6, 10
Choose the fact family formed by these numbers.
A.
10 – 6 = 4
10 – 6 = 4
4 + 6 = 10
4 + 6 = 10
B.
10 – 6 = 4
10 – 4 = 6
4 + 6 = 10
6 + 4 = 10
C.
4 + 6 = 10
10 – 6 = 4
D.
6 + 4 = 10
10 – 4 = 6
Answer:
The student's z-score will not change
Explanation:
Z-scores are used to compare results of an individual or entity to the average population's scores.
Since the adjustment of additional points is added to each class member's score, the adjustment will shift the entire distribution of scores. However, there will not be a change in the relative position of the student's score in the class. As a result, the student's z-score will not change.
