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-Dominant- [34]
3 years ago
10

What is the slope of a line that is perpendicular to the line y = x + 5? –2 -1/2 1/2 2

Mathematics
1 answer:
Sliva [168]3 years ago
7 0

y = x + 5


If it's perpendicular the slope is the opposite inverse of the other line,


The slope of line y = x + 5 is 1, because it's the number before x, so, the opposite inverse would be -1/1 = -1.

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Hey!

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~~~~~~~~~~~~~~~~~~~~~~~

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Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

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now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

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------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
%  (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


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